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Question 8: You toss a coin straight upward in a train which is moving at a constant velocity. If the air friction is negligible, the coin will land (a) In front of you (b) behind you (c) on your hand (d) at either in front of you or behind you

User Jfly
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1 Answer

6 votes

Answer:

(c) On your hand

Step-by-step explanation:

As we know that Second law of Newton's,It states that rate of the change in the linear momentum is known as force.


F=(dP)/(dt)=m(dv)/(dt) ( P = m v)

m=mass

P= Momentum

v=velocity

The velocity is constant then


(dv)/(dt)=0

Therefore
F=m(dv)/(dt)

F= 0

It means that acceleration or de -acceleration of the train is zero.

We can say that train is moving with steady motion,then the coin will return in the hand.

Therefore the answer is C.

User Dov Grobgeld
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