Answer:
The dimension of dog run are 15 feet length and 8 feet width.
Explanation:
Given:
Jimmy made rectangular fencing of 46 feet.
Hence we can say Perimeter of rectangle = 46 feet.
Let the width(w) be x.
Also Given he wants length to be 7 feet longer than the width.
Hence Length(l) =
![x+7](https://img.qammunity.org/2020/formulas/mathematics/high-school/wbli45xibbw5um1kjyo9rots9vegdgweor.png)
Now we know that Perimeter of rectangle is twice the sum of length and width.
Framing in equation for we get;
Perimeter of rectangle =
![2(l+w)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/p49vgs78g7ez85c1uxd9mdp575mu2q8f8e.png)
![2(x+7+x) = 46\\2(2x+7)=46\\4x+14=46\\4x=46-14\\4x=32\\x=(32)/(4)=8\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/5y3ijdn5jcd0ftqaqnankl0ybw0vo320t5.png)
Hence width = 8 ft.
Length =
![x+7=8+7=15\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/cfra46hee0h2ejkkod53trfcjvec7xrbot.png)
Hence the dimension of dog run are 15 feet length and 8 feet width.