Question

Find this awnser and ur the best​

Answer 1

1)Perimeter=23.20 cm

Area = 32.96
`cm^(2)`

2)Perimeter= 32.93 m

Area= 77.70
`m^(2)`

Explanation:

1) The above problem can be broken in 2 parts, rectangle with 3 sides and a semicircle.

The perimeter can be given as, for rectangle,

=
`(2)(6.2) + 2(2.1) = 16.6 cm`

The perimeter of semicircle can be given by,

=
`\pi (R) = \pi (2.1) = ((22)/(7))(2.1) = 6.6cm`

Thus, the total perimeter is =
`16.6 + 6.6 = 23.2`

The area can be found as, for rectangle,

=
`(6.2)(4.2) = 26.04 cm^(2)`

for semicircle,

=
`(\pi(R^(2)))/(2) = (\pi((2.1)^(2)))/(2) = 6.9237cm^(2)`

Thus, the total area is =
`26.04 + 6.9237 = <strong>32.9637cm^(2)`

2) This figure can be broken into semicircle and triangle with one side open.

The perimeter is given by, of triangle,

=
`(2)(7.9) = 15.8 m`

of semicircle,

=
`\pi (R) = \pi (5.45) = 17.1285m`

Thus, the total perimeter is =
`17.1285 + 15.8 =<strong> 32.9285m`

The, total area is given by,

A = area of triangle + area of semicircle

A =
`((1)/(2))(10.9)(5.7) + ((\pi(5.45)^(2))/(2)) = 31.065 + 46.632 = 77.697m^(2)`