Question

Jaimes has $2.60 in dimes and nickels. The number of dimes is 14 more than the number of nickels. How many of each coin does he have?

Answer 1

The number of dimes is 22 and the number of nickels is 8.

Explanation:

Given:

Jaimes has $2.60 in dimes and nickels.

The number of dimes is 14 more than the number of nickels.

Now, to find the each coin he have.

Let the dimes be
`10D`.

And the nickel be
`5N`.

(As 1 dime = 10 cent and 1 nickel = 5 cent)

As given in question:

`10D+5N=260`............(1)

`D=N+14`...................(2) (The number of dimes is 14 more than number of nickels.)

Now, solving the equation (1):

`10D+5N=260`

Putting the value of equation (2) on place D we get:

`10(N+14)+5N=260`.

`10N+140+5N=260`.

`15N+140=260`.

Subtracting both sides by 140 we get:

`15N=120`.

Dividing both sides by 15 we get:

`N=8`.

The number of nickels = 8.

And the number of dimes = (N+14) = 8+14=22.

Therefore, the number of dimes is 22 and the number of nickels is 8.