Question

What mass of ammonia is formed when 3.75 grams of nitrogen gas react with hydrogen gas according to the balanced chemical equation: N2 (g) + 3H2 (g) --> 2NH3 (g)?

3.75 g

4.55 g

7.50 g

9.10 g

Answer 1

Mass = 4.55 g

Step-by-step explanation:

Given data;

Mass of nitrogen = 3.75 g

Mass of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles =3.75 g / 28 g/mol

Number of moles = 0.134 mol

Now we compare the moles ammonia with nitrogen

N₂ : NH₃

1 : 2

0.134 : 2/1 ×0.134 = 0.268 mol

Theoretical yield:

Mass = number of moles × molar mass

Mass =0.268 mol × 17 g/mol

Mass = 4.55 g