Question

What is the Reynolds number for blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 × 10-3 Pa·s, a density of 1050 kg/m3, and travels at a mean fluid velocity of 28.9 cm/s?

Answer 1

Reynolds number will be 2416.3611

Step-by-step explanation:

We have given diameter of aorta d = 2.15 cm = 0.0215m

Dynamic viscosity of blood
`\mu =0.0027Pa-sec`

Fluid velocity
`\v =28.9cm/sec=0.289m/sec`

Fluid density
`\rho =1050kg/m^3`

We have to find the Reynolds number

We know that Reynolds number is given by

`R=(\rho vd)/(\mu )=(1050* 0.289* 0.0215)/(0.0027)=2416.3611`