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A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise. Apportion the class load using the Hamilton Method.

User Gaj Julije
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Answer:

The final curse load of the local gym instructor is this:

High-­‐impact aerobics = 1

Low-­‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

The final course load is this:

High-­‐impact aerobics = 1

Low-­‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

User Teepark
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