Question

An 8.8?g ice cube is placed into 250g of water.Calculate the temperature change in the water upon the complete melting of the ice. Assume that all of the energy required to melt the ice comes from the water. Express your answer in terms of the initial temperature of water, T.

Answer 1

Step-by-step explanation:

The given data is as follows.

mass of ice = 8.8 g, mass of water = 250 g

It is known that latent heat of fusion of ice is 333 J/g. Then, heat energy of ice will be calculated as follows.

Q =
`m * L_(f)`

=
`8.8 g * 333 J/g`

= 2930.4 J

As heat absorbed by water = heat released by ice

`250 g * 4.18 J/g^(o)C * \Delta T` = 2930.4 J

`\Delta T` = 2.8°C

thus, we can conclude that the temperature change in the water upon the complete melting of the ice is 2.8°C.