Question

Frieda stands on a hill with a slope of 12°. If her mass is 65 kg, what is the

magnitude of the normal force acting on her?

Answer 1

Normal force on Frieda is 623.71N

Step-by-step explanation:

Given that Frieda stands on a hill with a slope of 12°

Let mass of Frieda is m=65kg

θ is slope of hill = 12°

Figure show that free body diagram of Frieda standing on hill if slope 12°

From free body diagram,

Normal force = mgcosθ

= (65)(9.81)(cos12)

= (65)(9.81)(0.9781)

= 623.71N

Thus, normal force on Frieda is 623.71N