Question

Two satellites are in circular orbits around a planet that has radius 9.00×106 m. One satellite has mass 68.0 kg, orbital radius 8.00×107 m , and orbital speed 4800 m/s. The second satellite has mass 84.0 kg and orbital radius 7.00×107

What is the orbital speed of this second satellite?

Answer 1

v₂ = 5131.42 m/s

Step-by-step explanation:

given,

radius of the planet = r₁ = 9.00×10⁶ m

mass of the satellite = m₁ = 68 Kg

orbital radius = r₁ = 8 x 10⁷ m

orbital speed = v₁ = 4800 m/s

mass of second satellite = m₂ = 84.0 kg

orbital radius = r₂ = 7.00×10⁷ m

orbital speed of second satellite = v₂ = ?

using orbital speed of satellite

`v = \sqrt{(GM)/(r)}`

so,

`v \alpha (1)/(√(r))`

now,

`(v_1)/(v_2) =\sqrt{(r_2)/(r_1)}`

`(v_2)/(4800) =\sqrt{(8* 10^7)/(7 * 10^7)}`

v₂ = 5131.42 m/s

The orbital speed of second satellite is equal to v₂ = 5131.42 m/s