Question

If a car's acceleration is 600 m/s^2 and its time is 3 seconds, what is its Δv? (please explain)

Answer 1

The velocity required to accelerate the object is 1800 m/s.

Step-by-step explanation:

When the velocity of an object changes rapidly, the object is said to be accelerating.

Acceleration can be defined as the rate of change of velocity with respect to time.

It can be formulated as,

`\begin{aligned}&a=\lim \left((\Delta v)/(\Delta t)\right)=\left((d v)/(d t)\right)\\&\Delta t \rightarrow 0\end{aligned}`

`a=\left((d v)/(d t)\right)=\left((d)/(d t)\right) \cdot\left((d s)/(d t)\right)=\left((d^(2) s)/(d t^(2))\right)`

Given:

Acceleration = 600
`m/s^2`

Time = 3 seconds

`\begin{array}{l}{a=\left((d v)/(d t)\right)} \\ \\{600=\left((\Delta v)/(3)\right)} \\ \\{\Delta v=600 * 3=1800 \mathrm{m} / \mathrm{s}}\end{array}`