Question

find an equation for the line which passes through (-6,-4) and is perpendicular to the line given by y=3/4x-1/2

Answer 1

Explanation:

We see that if a line is perpendicular to the line
`y = (3)/(4)x - (1)/(2)`, then the slope of the line is
`-(4)/(3)` since the slopes of two perpendicular lines must multiply to -1. Knowing this, we get the following equation:
`y = -(4)/(3)x + b`, and we can find out b by plugging in the x and y that we know. In this case,
`-4 = -(4)/(3) \cdot -6 + b`, so we get
`b = -12`. Plugging it back into the equation, we get the final equation of
`\boxed{y = -(4)/(3)x - 12}`