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What is the Min/Max Value of this equation:

8x² - 29x + 2

(Please provide work so I can see how you got the answer! THANK YOU!)

1 Answer

6 votes

Answer:

The maximum value for this equation is 3.55 (rounding to two decimal places) and the minimum value is 0.07 (rounding to two decimal places).

Explanation:

1. Let's use the quadratic formula to find the max and min value for x:

x = [ - (-29) +/- (√29² - 4 * 8 * 2)]/2*8

x = [ 29 +/- (√29² - 64)]/16

x = [ 29 +/- (√841 - 64)]/16

x = [ 29 +/- (√777)]/16

x = [ 29 +/- 27.87]/16

x₁ = [29 + 27.87]/16

x₂ = [29 - 27.87]/16

x₁ = 56.87/16

x₂ = 1.13/16

x₁ = 3.55

x₂ = 0.07

User Kellyfj
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