Answer:
P-value = 0.3085
Explanation:
The null and alternative hypothesis is,
H0 is μ 175
Ha is μ > 175
x’ = 180
σ = 20
n = 4
Test statistic = z = ( x’ - mew) / / √n
= (180 - 175) / 20 / 4
Test statistic = z = 0.50
This is the right tailed test
p(Z > 0.50) = 1-P (Z < 0.50) = 1 - 0.6915
P-value = 0.3085