Question

. A 5 kg turkey and a 3.5 kg turkey are suspended on opposite sides of a single pulley.

a) How hard are the turkeys pulling on each other (Ft)

b) how quickly will the set accelerate?

Answer 1

a) 40.3725 N

b)
`a=1.729 m/s^2`

Step-by-step explanation:

mass of turkey 1 M= 5 kg

mass of turkey 2 m= 3.5 kg

Let T be the tension in the string and a be the acceleration of the system

then from FBD in the attachment

T-mg=ma.................1

Mg-T=Ma..................2

from 1 and 2 we find a as

`a= (Mg-mg)/(M+m)`

now substituting the values we get

`a= (5g-3.5g)/(5+3.5)`

`a= (1.5g)/(8.5)`

`a=1.729 m/s^2`

now from equation 1 we can calculate Tension T as

T-mg=ma

T= m(a+g)

T= 3.5(1.729+9.81)= 40.3725 N