Question

Tom Cruise jumped from one building to other building while filming the roof chase scene in Mission: Impossible - Fallout. He did not land on the roof of the other building safely and broke his ankle. If we assume the heights of the two building are the same and the distance between the buildings is 5 m, what is the minimum speed to land on the roof of the other building? Assume the jumping angle is 15 degrees and the air friction is negligible. (15 points) Vo =? O = 15° D = 5 m

Answer 1

`v_0=9.9\ m.s^(-1)`

Step-by-step explanation:

Given:

• angle of launch of projectile from horizontal,
  `\theta=15^(\circ)`

• range of projectile,
  `R=5\ m`

We have formula for the range of projectile:

`R=(v_0^2* sin\ 2\theta)/(g)`

putting the respective values

`5=(v_0^2* sin\ 30^(\circ))/(9.8)`

`v_0=9.9\ m.s^(-1)` is the velocity with which Tom should jump to land on the other roof.