Question

Help me with my assignment please.

Factor the ff.

1.) x² + 4x + 3
2.) y² - 5y + 6
3.) x² - 5x - 36
4.) y² + 5y - 14​

Answer 1

Explanation:

`1)\\x^2+4x+3=\\x^2+3x+x+3=\\(x)(x+3)+(1)(x+3)=\\(x+3)(x+1)`

`2)\\y^2-5y+6=\\y^2-3y-2y+6=\\(y)(y-3)-(2)(y-3)=\\(y-3)(y-2)`

`3)\\x^2-5x-36=\\x^2-9x+4x-36=\\(x)(x-9)+(4)(x-9)=\\(x-9)(x+4)`

`4)\\y^2+5y-14=\\y^2+7y-2y-14=\\(y)(y+7)-(2)(y+7)=\\(y+7)(y-2)`

Answer 2

see explanation

Explanation:

1

x² + 4x + 3

consider the factors of the constant term (+ 3) which sum to give the coefficient of the x- term (+ 4)

the factors are + 1 and + 3 , since

1 × 3 = + 3 and 1 + 3 = + 4 , then

x² + 4x + 3 = (x + 1)(x + 3)

2

y² - 5y + 6

consider the factors of the constant term (+ 6) which sum to give the coefficient of the y- term (- 5)

the factors are - 3 and - 2 , since

- 3 × - 2 = + 6 and - 3 - 2 = - 5 , then

y² - 5y + 6 = (y - 3)(y - 2)

3

x² - 5x - 36

consider the factors of the constant term (- 36) which sum to give the coefficient of the x- term (- 5)

the factors are - 9 and + 4 , since

- 9 × 4 = - 36 and - 9 + 4 = - 5 , then

x² - 5x - 36 = (x - 9)(x + 4)

4

y² + 5y - 14

consider the factors of the constant term (- 14) which sum to give the coefficient of the y- term (+ 5)

the factors are - 2 and + 7 , since

- 2 × 7 = - 14 and - 2 + 7 = + 5 , then

y² + 5y - 14 = (y - 2)(y + 7)