Question

(a) Calculate the absolute pressure at the bottom of a fresh-water lake at a depth of 28.8 m. Assume the density of the water is 1.00 ✕ 103 kg/m3 and the air above is at a pressure of 101.3 kPa.

Answer 1

383828 Pa

Step-by-step explanation:

`P_0` = Atmospheric pressure =
`101.3* 10^3\ Pa`

`\rho` = Density of water = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth = 28.8 m

Absolute pressure is given by

`P=P_0+\rho gh\\\Rightarrow P=101.3* 10^3+1000* 9.81* 28.8\\\Rightarrow P=383828\ Pa`

The absolute pressure at the bottom of the fresh water lake is 383828 Pa