Question

A clock mechanism at rest has a period of exactly 1 second. When this clock is observed while moving with a speed of 0.79 c, what is its period?

Answer 1

1.63103 seconds

Step-by-step explanation:

`\Delta t` = Actual period of clock = 1 second

v = Speed at which the observer is moving = 0.79 c

c = Speed of light =
`3* 10^8\ m/s`

Time dilation is given by

`\Delta t'=\frac{\Delta t}{\sqrt{1-(v^2)/(c^2)}}\\\Rightarrow \Delta t'=\frac{1}{\sqrt{1-(0.79^2c^2)/(c^2)}}\\\Rightarrow \Delta t'=1.63103\ s`

The period is 1.63103 seconds