Question

A car traveling 23 m/s begins to decelerate at a constant rate of 5 m/s^2 . After how many seconds does the car come to a stop? (Use symbolic notation and fractions where needed.)

Answer 1

The car comes to a stop after 4.6 seconds.

Step-by-step explanation:

To find the time it takes for the car to come to a stop, we can use the equation:

v = u + at

In this equation:
- v is the final velocity, which is 0 m/s because the car comes to a stop
- u is the initial velocity, which is 23 m/s
- a is the acceleration, which is -5 m/s² because the car is decelerating
- t is the time

Substituting the known values into the equation:

0 = 23 + (-5)t

Simplifying the equation:

-5t = -23

t = 23/5

Therefore, the car comes to a stop after 4.6 seconds.

Answer 2

t = 4.6 s

Step-by-step explanation:

given,

initial velocity of the car = 23 m/s

declaration rate of car = 5 m/s²

final velocity of the car = ?

time taken to stop the car = ?

using equation of motion to solve the question

v = u + a t

v is final velocity

u is the initial velocity

0 = 23 - 5 t

we have used negative sign because there is deceleration

5 t = 23

`t = (23)/(5)`

t = 4.6 s

time taken to stop the car is equal to t = 4.6 s