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What’s the 38th term of the arithmetic sequence 31,40,49,58?

User DaveJenni
by
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1 Answer

0 votes

Answer:


a_3_8=364

Explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference

we have


31,40,49,58,...

Let


a_1=31\\a_2=40\\a_3=49\\a_4=58

we have that


a_2-a_1=40-31=9


a_3-a_2=49-40=9


a_4-a_3=58-49=9

so

The common difference is equal to 9

We can write an Arithmetic Sequence as a rule:


a_n=a_1+d(n-1)

where

a_n is the nth term

a_1 is the first term

d is the common difference

n is the number of terms

Find the 38th term of the arithmetic sequence

we have


a_1=31\\d=9\\n=38

substitute the values


a_3_8=31+9(38-1)


a_3_8=31+9(37)


a_3_8=364

User Roverred
by
4.7k points
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