Answer:
![a_3_8=364](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mfv7k3fx3b8n2xvzca5kd3u12ryicg7tz2.png)
Explanation:
we know that
In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference
we have
![31,40,49,58,...](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s8lh89x2o8bivc5xxz3913nuyp692dmrag.png)
Let
![a_1=31\\a_2=40\\a_3=49\\a_4=58](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2mu62dy2km5isv5elbxq184j4gmqpyp3h9.png)
we have that
![a_2-a_1=40-31=9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y6rfsa6asu937slkq7ye1odderdl7a1lsm.png)
![a_3-a_2=49-40=9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wq8omm86b7h9aq7jr9qecexoqkrjig4uqw.png)
![a_4-a_3=58-49=9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/njoopmvo7xn6kq7tionuw6tg9bl691yzuw.png)
so
The common difference is equal to 9
We can write an Arithmetic Sequence as a rule:
![a_n=a_1+d(n-1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ubsa8ruizynnpnuo1w20syq2ij3srxp658.png)
where
a_n is the nth term
a_1 is the first term
d is the common difference
n is the number of terms
Find the 38th term of the arithmetic sequence
we have
substitute the values
![a_3_8=31+9(38-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pmszcdejbrfvgi2x6xzkptw3z53u6ylock.png)
![a_3_8=31+9(37)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/csewdpng0l2jsomn2uz2if3p39krphspk3.png)
![a_3_8=364](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mfv7k3fx3b8n2xvzca5kd3u12ryicg7tz2.png)