Question

Suppose you have a 0.10 M solution of AlBr3. What is the concentration of each ion? A. 0.10 M Al3+ ions and 0.30 M Br- ions B. 0.30 M Al3+ ions and 0.10 M Br- ions C. 0.10 M Al3+ ions and 0.033 M Br- ions D. 0.033 M Al3+ ions and 0.033 M Br- ions

Answer 1

Answer: The concentration of
`Al^(3+)` ions is 0.10 M and that of
`Br^-` ions is 0.30 M

Step-by-step explanation:

We are given:

Concentration of
`AlBr_3` = 0.10 M

The chemical equation for the ionization of aluminium bromide follows:

`AlBr_3\rightarrow Al^(3+)+3Br^-`

1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions

So, concentration of aluminium ions = 0.10 M

Concentration of bromide ions =
`[(3* 0.1)]=0.3M`

Hence, the concentration of
`Al^(3+)` ions is 0.10 M and that of
`Br^-` ions is 0.30 M