Question

A 581.2 mL sample of carbon dioxide was heated to 347 K.

If the volume of the carbon dioxide sample at 347 K is 830.5 mL, what was its temperature at 581.2 mL?

Answer 1

The temperature at 581.2 mL volume was 242.8 K.

Step-by-step explanation:

Using Charle's law

`\frac {V_1}{T_1}=\frac {V_2}{T_2}`

Given ,

V₁ = 581.2 mL

V₂ = 830.5 mL

T₁ = ?

T₂ = 347 K

Using above equation as:

`\frac {581.2\ mL}{T_1}=\frac {830.5\ mL}{347\ K}`

`T_1=(581.2* 347)/(830.5)\ K=242.8\ K`

The temperature at 581.2 mL volume was 242.8 K.