Question

A box with a mass of 3.00 kg starts from rest at the top of a 34.5° incline and slides 2.00 m down the incline in 1.55 as. (a) What is the magnitude of the acceleration of the box (in m/s2)

Answer 1

The magnitude of the acceleration of the box is 1.664 m/s².

Step-by-step explanation:

Given that,

Mass of box = 3.00 kg

Angle = 34.5°

Distance = 2.00 m

Time = 1.55 s

We need to calculate the magnitude of the acceleration of the box

Using equation of motion

`s = ut+(1)/(2)at^2`

`a=(2s)/(t^2)`

Where, s = distance

t = time

a = acceleration

Put the value into the formula

`a=(2*2.00)/(1.55^2)`

`a=1.664\ m/s^2`

Hence, The magnitude of the acceleration of the box is 1.664 m/s².