Question

A solenoid 83.0 cm long has a radius of 2.10 cm and a winding of 1600 turns; it carries a current of 3.60 A. Calculate the magnitude of the magnetic field inside the solenoid.

Answer 1

B = 0.0087 T

Step-by-step explanation:

given,

Length of solenoid (L)= 83 cm = 0.83 m

radius of the solenoid (r)= 2.10 cm = 0.021 m

number of turns (N)= 1600 turns

current (I)= 3.60 A

Using magnetic field formula

`B = (\mu_0Ni)/(L)`

`B = (4 \pi * 10^(-7) * 1600 * 3.6)/(0.83)`

B = 0.0087 T

the magnitude of magnetic field inside the solenoid is equal to B = 0.0087 T