Question

A quantity of mercury occupies 400.0 cm^3 at 0°C. What volume will it occupy when heated to 50°C? Mercury has a volume expansion coefficient of 180 × 10^-6 K-1. A) 450 cm^3B) 409.7 cm^3C) 403.6 cm^3D) 401.8 cm^3

Answer 1

Answer : The correct option is, (C)
`403.6cm^3`

Explanation :

The formula used for the volume expansion coefficient is:

`V_(final)=V_(initial)* (1+\gamma \Delta T)`

where,

`V_(final)` = final volume of mercury = ?

`V_(initial)` = initial volume of mercury =
`400.0cm^3`

`\gamma` = volume expansion coefficient =
`180* 10^(-6)K^(-1)`

`\Delta T` = change in temperature =
`50^oC-0^oC=50^oC`

Now put all the given values in the above formula, we get:

`V_(final)=400.0* [1+(180* 10^(-6)* 50)]`

`V_(final)=403.6cm^3`

Therefore, the final volume of mercury is
`403.6cm^3`