Answer:
I)E= 40.95 GPa
II)E=5.29 GPa
Step-by-step explanation:
I)
Given that
E₁ = 2.41 GPa ,V₁=1-0.55 = 0.45
E₂ = 72.5 GPa ,V₂=0.55
Longitudinal moduli given as ;
E= E₁V₁+E₂V₂
E= 2.41 x 0.45 + 72.5 x 0.55 GPa
E= 40.95 GPa
II)
E₁ = 2.41 GPa ,V₁=1-0.55 = 0.45
E₂ =230 GPa ,V₂=0.55
Transverse moduli given as:
![(1)/(E)=(V_1)/(E_1)+(V_2)/(E_2)](https://img.qammunity.org/2020/formulas/engineering/college/atzvfvs3657dv7ukm5pglyv8m6a3rcpgr7.png)
![(1)/(E)=(0.45)/(2.41)+(0.55)/(230)](https://img.qammunity.org/2020/formulas/engineering/college/r5wxgcy0zdld45mkhasl3biigjo1uu1dno.png)
E=5.29 GPa