Answer:

Step-by-step explanation:
the formula to calculate the intensity, given the power:

Where
is intensity, and
is the power that the wave carries in a given area
. In this case:
, and the area since the speaker emits the sound equally in all directions is the area of a surface of a sphere with a radius of
:

replacing the radius value:





So, now that we know the area we can calculate the intensity:



the sound intensity at the distance of 2.00m from the speaker is
