Question

A raindrop has a mass of 50. mg and the Pacific Ocean has a mass of 7.08 X 10^20 kg. Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of raindrops? Round your answer to 2 significant digits. How many moles of raindrops are in the Pacific Ocean? Round your answer to 2 significant digits.

Answer 1

Step-by-step explanation:

It is known that according to mole concept, 1 mole of every substance contains
`6.022 * 10^(23)` atoms.

Therefore, mass of 1 mole of raindrops is as follows.

Mass of 1 mole raindrops = mass of 1 rain drop × Avogadro's number

=
`50 * 6.022 * 10^(23)`

=
`301.1 * 10^(23)` mg

or, =
`3.0 * 10^(22)` (as 1 mg = 0.001 g)

Therefore, mass of 1 mole of raindrops is
`3.0 * 10^(22)` g.

Now, the mass of Pacific ocean is calculated as follows.

Mass of Pacific ocean =
`\frac{\text{mass of pacific ocean}}{\text{mass of 1 mole of raindrops}}`

As 1 kg = 1000 g. So, mass of Pacific ocean will be
`7.08 * 10^(20) kg` equal to
`7.08 * 10^(23) g`.

Hence, moles of raindrops will be calculated as follows.

Mass of Pacific ocean =
`\frac{\text{mass of pacific ocean}}{\text{mass of 1 mole of raindrops}}`

=
`(7.08 * 10^(23))/(3.0 * 10^(22))`

= 24 moles

Therefore, we can conclude that 24 moles of raindrops are in the Pacific Ocean.