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What is the daughter nucleus (nuclide) produced when ^103Mo undergoes beta decay by emitting an electron?

User Cool Blue
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Answer:\left \{ {{y=103} \atop {x=43}} \right T_{C}

Step-by-step explanation:

The equation for the reaction is shown below.

\left \{ {{y=103} \atop {x=42}} \right M_{O} ⇒ \left \{ {{y=103} \atop {x=43}} \right T_{C} + \left \{ {{y=0} \atop {x=-1}} \right e

Beta radiations are made up of the electron particle with mass number 0 and atomic number -1. Hence when a parent nuclide undergoes a beta decay, the resulting daughter nuclide will have an atomic number greater by 1.The resulting daughter nuclide is technetium with mass number 103 and atomic number 43

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