Answer:\left \{ {{y=103} \atop {x=43}} \right T_{C}
Step-by-step explanation:
The equation for the reaction is shown below.
\left \{ {{y=103} \atop {x=42}} \right M_{O} ⇒ \left \{ {{y=103} \atop {x=43}} \right T_{C} + \left \{ {{y=0} \atop {x=-1}} \right e
Beta radiations are made up of the electron particle with mass number 0 and atomic number -1. Hence when a parent nuclide undergoes a beta decay, the resulting daughter nuclide will have an atomic number greater by 1.The resulting daughter nuclide is technetium with mass number 103 and atomic number 43