Question

In a two-slit interference experiment, the path length to a certain point P on the screen differs for one slit in comparison with the other by 1.25λ.What is the phase difference between the two waves arriving at point P?

Answer 1

δ = 2.5 π

Step-by-step explanation:

Given that

d= 1.25 λ

d= Path length

We know that phase difference(δ) given as

`\delta =2\pi (dsin\theta)/(\lambda)`

`dsin\theta = 1.25\lambda`

Now by putting the value

`\delta =2\pi (dsin\theta)/(\lambda)`

`\delta =2\pi (1.25\lambda)/(\lambda)`

δ = 2.5 π

Therefore the phase difference will be 2.5π