Question

A standard galvanic cell is constructed with Cu2+ | Cu and I2 | I- half cell compartments connected by a salt bridge. Which of the following statements are correct?Hint: Refer to a table of standard reduction potentials.(Choose all that apply.)I2 is reduced at the cathode.I- is oxidized at the anode.The anode compartment is the Cu2+|Cu compartment.In the external circuit, electrons flow from the Cu2+|Cu compartment to the I2|I- compartment.As the cell runs, anions will migrate from the Cu2+|Cu compartment to the I2|I- compartment.

Answer 1

Answer: The correct statement are following.

• 
  `I_(2)` is reduced at the cathode.

• In the external circuit, electrons flow from the
  `Cu^(2+)|Cu` compartment to the
  `I2|I^(-)` compartment.

Step-by-step explanation:

An oxidizing agent is defined as a substance which readily accepts an electron and itself gets reduced in order to oxidize another substance in a chemical reaction.

So, as per the given data the reaction equations are as follows.

`Cu^(2+) + 2e^(-) \rightarrow Cu(s)`,
`E_(o)` = +0.337

`I_(2)(s) + 2e^(-) \rightarrow 2I`,
`E_(o)` = +0.54

Lower or less negative is the
`E_(o)` value, more easily the element or substance can lose electrons. This means that the element itself gets oxidized and reduces the other element or substance.

As per the given data,
`I^(-)` electrode acts as cathode and
`Cu^(-)` electrode acts as anode.

• Hence,
  `I_(2)` is reduced at cathode. And, the anode compartment is
  `Cu^(2+)|Cu` compartment.

• Also, in the external circuit electrons flow from
  `Cu^(2+)|Cu` to the
  `I_(2)|I^(-)` compartment.