Question

neutrons have a mass of 1.675×10 to the negative 27th. determine the kinetic energy of a neutron traveling 20. 5% of the speed of light

Answer 1

The K.E of the neutron is, K.E = 5.025 x 10⁻²⁰ J

Step-by-step explanation:

Given data,

The mass of the neutron, m = 1.675 x 10⁻²⁷ kg

The velocity of the neutron, v = 20.5% of c

The speed of light, c = 3 x 10⁸ m/s

v = 20.5% of c

= 3 x 10⁸ x 20 / 100

= 6 x 10⁷ m/s

The K.E of the neutron is,

K.E = ½ mv²

= ½ x 1.675 x 10⁻²⁷ x 6 x 10⁷

= 5.025 x 10⁻²⁰ J

Hence, the K.E of the neutron is, K.E = 5.025 x 10⁻²⁰ J