Answer:
(2, -3)
Explanation:
To solve a system of equations means to find the intersection point of the lines. For this system, you can use substitution.
Rearrange x-2y=8 so that "x" is by itself on one side.
x - 2y = 8
x = 8 + 2y (Use this equation for substitution because it equates to a variable)
In the other equation 3x-2y=12, substitute x for 8+2y.
3x - 2y = 12 Change x to the equation
3(8+2y) - 2y = 12 Use the distributive property and expand
24 + 6y - 2y = 12 Collect liked terms
24 + 4y = 12
4y = 12 - 24 Subtract 24 from both sides to start isolating y
4y = -12
y = -12/4 Divide 4 from both sides to isolate y
y = -3
Substitute y= -3 into any one of the equations. I will use x-2y=8.
x - 2y = 8 Change y to -3
x - 2(-3) = 8 Simplify
x - (-6) = 8
x + 6 = 8 Subtract 6 from both sides
x = 2
Therefore the solution is (2, -3).