Question

An oscillating LC circuit consists of a 61.5 mH inductor and a 3.77 μF capacitor. If the maximum charge on the capacitor is 3.56 μC, what are (a) the total energy in the circuit and (b) the maximum current? (a) Number Enter your answer for part (a) in accordance to the question statement Units Choose the answer for part (a) from the menu in accordance to the question statement

Answer 1

a. U = 1.68 μJ

b. i = 7.39 mA

Step-by-step explanation:

a.

The energy total of the circuit can be find using

U = Q ² / 2 * C

Q = 3.56 μC

C = 3.77 μF

U = (3.56 μC ) ² / 2 * 3.77 μF

U = 1.6808 x 10 ⁻⁶ J

U = 1.68 μJ

b.

Now to determine the current in the circuit

U = ¹/₂ * L * i²

i² = 2 * U / L

i = √ 2 * U / L

i = √2 * 1.68 μJ / 61.5 mH

i = 7.39 mA