Answer:
11025 W
Step-by-step explanation:
Given that athlete can lift a mass of 900 kg by 2·5 m in 2 s
Average power output is defined as the work done per unit time
∴ Average power output = (work done) ÷ (time taken)
Here on the object the force that acts is the weight of that object
∴ Force on that object = (mass of the object) × (acceleration due to gravity) = 900 × 9·8 = 8820 N
∴ Person requires this much force to lift that object
Work done on the object is defined as the dot product of force and displacement
∴ Work done = 8820 × 2·5 =22050 J
Power = 22050 ÷ 2 = 11025 W
∴ Average power output of the athlete = 11025 W