Slope of a line perpendicular to a line whose equation is -4x - 2y + 18 = 0 is
Solution:
Given that the line equation is -4x - 2y + 18 = 0
We have to find the slope of line perpendicular to the above line equation
Let us first find the slope of given line
The slope intercept form of a line is given as:
y = mx + c
where "m" is the slope of line and "c" is the y - intercept
Given equation of line is:
-4x - 2y + 18 = 0
Let us rearrange the above equation into slope intercept form
2y = -4x + 18
y = -2x + 9
Comparing y = -2x + 9 with general slope intercept form y = mx + c, we get,
m = -2
Thus the slope of give line equation is -2
Now we have to find the slope of line which is perpendicular to given line having equation -4x - 2y + 18 = 0 and slope -2
Since the lines are perpendicular, product of slopes of both lines is equal to -1
Slope of line perpendicular to given line x slope of given line = -1
Slope of line perpendicular to given line x -2 = -1
Slope of line perpendicular to given line =
Thus slope of a line perpendicular to a line whose equation is -4x - 2y + 18 =0 is