Question

Professional Application. A 98 kg football player catches a 0.750 kg ball with his feet off the ground with both of them moving horizontally. The player's speed is 5.35 m/s, and the ball's speed is 25.9 m/s. (a) First, consider the situation where the player and the ball are going in the same direction, and take this direction as positive. Calculate their final velocity (in m/s).

Answer 1

`V_s = 5.5 m/s`

Step-by-step explanation:

a)

We will use the conservation of the linear momentum:

`P_i =P_f`

so:

`M_pV_p +M_bV_b = M_sV_s`

Where
`M_p` is the mass of the football player,
`V_p` is the velocity of the football player,
`M_b` is the mass of the ball,
`V_b` is velocity of the ball,
`M_s` is the mass of both after the collition and
`V_s` is the Velocity of both after the collition.

`(98 kg)(5.35 m/s) +(0.750 kg)(25.9 m/s) = (98 kg + 0.750 kg)V_s`

Solving for
`V_s`, we get:

`V_s = 5.5 m/s`