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The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

in seconds. A high-speed camera is ready to film the person between 15 m and 10 m above the ground. For which interval of
time should the camera film the person?
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User Squarism
by
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2 Answers

2 votes

Answer:

B

Explanation:

took the unit test

User Schroedingers Cat
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5 votes

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:


1\leq t\geq √(2)

Explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation


h =20-5t^(2)-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height
h = 15m

Put height value in equation 1


15 =20-5t^(2)


5t^(2) =20-15


5t^(2) =5


t^(2) =1


t =\pm1

We know that the time is always positive, therefore
t=1

when the stuntman is 10m above the ground.

height
h = 10m

Put height value in equation 1


10 =20-5t^(2)


5t^(2) =20-10


5t^(2) =10


t^(2) =(10)/(5)


t^(2) =2


t=\pm√(2)


t=√(2)

Therefore ,time interval of camera film him is
1\leq t\geq √(2)

User Rover
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6.1k points