Question

Electrons are accelerated through a voltage difference of 120 kV inside a high voltage accelerator tube. What is the final kinetic energy of the electrons?

Answer 1

The final kinetic energy of electrons accelerated through a voltage difference of 120 kV is 120 keV.

Step-by-step explanation:

When an electron is accelerated through a voltage difference, its final kinetic energy can be calculated using the relationship between accelerating voltage and electron energy. An electron accelerated through a potential difference of 1 V is given an energy of 1 eV. Therefore, for a voltage difference of 120 kV, the final kinetic energy of the electrons would be 120 keV.

Answer 2

The final kinetic energy of the electrons is
`1.92 * 10^(-14)`

Step-by-step explanation:

According to the Special Theory of Relativity, when a particle is in motion with a constant velocity, it is a substantial fraction of the speed of light. To describe the motion of the moving particle, Einstein's special theory of relativity is required.

For the above-given question, it can be solved by using the below mention formula,

K = qV

where:

q is the charge

V is the potential difference

It is given that

V, Voltage difference is of 120 kV =
`120 * 10^(3) V`

q will be equal to e, q = e =
`1.6 * 10^(-19)`

`K=120 * 10^(2) V * 1.6 * 10^(-19)=1.92 * 10^(-14) J`