Question

A package is dropped from a helicopter moving upward at 15m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released?

Answer 1

Height of package initially = 1054.4 metre

Step-by-step explanation:

The package is dropped from a helicopter moving upward at 15 m/s.

Total time taken for the package to reach the ground = 16 seconds.

Initially , the package has an upward velocity and therefore it moves upwards ,reaches the topmost point and then falls down and finally strikes the ground.

Displacement , h = unknown

Time , t = 16 seconds

Initial velocity , u = 16 m/s

By equation of motion ,

s =
`u * t - 0.5 * g * t^(2)`

Acceleration , a = g = 9.8 m/
`s^(2)`

-s =
`15 * 16 - 0.5* 9.8* (16)^(2)`

-s = 240 - 1254.4

s = 1054.4 metres