Question

Two vessels are labeled A and B. Vessel A contains NH3 gas at 76°C, and vessel B contains Ne gas at the same temperature. If the average kinetic energy of NH3 is 7.1 × 10−21 J/molecule at 70°C, calculate the root-mean-square speed of Ne atoms in m/s.

Answer 1

`\pi^2 _(rms) =({3RT)/M}`

For te Ne as

T=76°C=76+273=349K

molecular mass of Ne=20.18g/mol=0.02018kg/mol

R=8.314J/K.mol ..the gas constant

using the formula

`\pi^2 _(rms) =({3*8.314*349)/0.02018}`

431355.69 j/kg

J=1kg
`(kg*m^2)/(s^2)`/(kg)

[tex]\pi^2 _{rms}=m^2/s^2

[tex]\pi _{rms}=m/s

therefore, taking the square root of 431355.69 j/kg

[tex]\pi _{rms}=656.77m/s