Question

Y=-8(x+3)(x-2) in standard form

Answer 1

`\large\boxed{y=-8x^2-8x+48}`

Explanation:

The standard form of an equation of a parabola:

`y=ax^2+bx+c`

We have

`y=-8(x+3)(x-2)` use distributive property: a(b + c) = ab + ac

`y=\bigg((-8)(x)+(-8)(3)\bigg)(x-2)`

`y=(-8x-24)(x-2)` use FOIL: (a + b)(c + d) = ac+ ad + bc + bd

`y=(-8x)(x)+(-8x)(-2)+(-24)(x)+(-24)(-2)`

`y=-8x^2+16x-24x+48` combine like terms

`y=-8x^2+(16x-24x)+48\\\\y=-8x^2-8x+48`