Question

Engineers are designing a hydraulic lift that can be used to repair trucks with a mass of 3600 kg . What ratio of piston areas would you suggest for the design if the maximum available external force is to be 2600 N

Answer 1

`(A_(s) )/(A_(p)) = (882)/(65)`

Step-by-step explanation:

Pascal principle

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

The pressure is definited like this:

P=F/A

Where:

P: Pressure in pascals (Pa)

F: Force acting in the area (N)

A : Area where the force acts (m²)

Pascal principle

Pp=Ps

Fp/ Ap= Fs/ As Formula (1)

Where :

Pp : Pressure on the primary piston

Ps : Pressure on the secondary piston

Fp : Force on the primary piston (N)

Fs: Force on the secondary piston ((N)

Ap: Primary piston area (m²)

As: Secondary piston area (m²)

Calculation of the weight of the truck (W)

W= m*g= 3600 kg*9.8m/s²= 35280 N

W = Fs

Data

Fp : Force on the primary piston = 2600 N

Fs= Force on the secondary piston= 35280 N

Calculation of ratio of piston areas

We replece data in the formula (1)

`(F_(p) )/(A_(p)) = (F_(s))/(A_(s))`

`(2600 )/(A_(p)) = (35280)/(A_(s))`

`(A_(s) )/(A_(p)) = (35280)/(2600)`

`(A_(s) )/(A_(p)) = (882)/(65)`