Question

Grams of sodium chloride in 30mL of a 1.2M solution​

Answer 1

Mass = 2.12 g

Step-by-step explanation:

Given data:

Volume of sodium chloride solution = 30 mL (30/1000 = 0.03 L)

Molarity = 1.2 M

Grams of sodium chloride = ?

Solution:

Molarity = number of moles / volume in litter

Number of moles = Molarity × volume in litter

Number of moles = 1.2 M × 0.03 L

Number of moles = 0.036 mol

Mass in grams:

Mass = number of moles × molar mass of sodium chloride

Mass = 0.036 mol × 58.5 g/mol

Mass = 2.12 g