Answer:
x = 3, y = 8
Explanation:
We know:
The diagonals of the parallelogram are divided in half.
Therefore
EK ≅ KG and HK ≅ KF.
We have
EK = 7x + 5, KG = 3x + 17, HK = 3y - 11 and KF = y + 5
Equations:
(1) 7x + 5 = 3x + 17
(2) 3y - 11 = y + 5
Solutions:
(1)
7x + 5 = 3x + 17 subtract 5 from both sides
7x + 5 - 5 = 3x + 17 - 5
7x = 3x + 12 subtract 3x from both sides
7x - 3x = 3x - 3x + 12
4x = 12 divide both sides by 4
4x/4 = 12/4
x = 3
------------------------------
(2)
3y - 11 = y + 5 add 11 to both sides
3y - 11 + 11 = y + 5 + 11
3y = y + 16 subtract y from both sides
3y - y = y - y + 16
2y = 16 divide both sides by 2
2y/2 = 16/2
y = 8