Question

A boxer punches a sheet of paper in midair from rest to a speed of 40 m/s in 0.05 s. If the mass of the paper is 0.01 kg, the force of the punch on the paper is?

Answer 1

8N

Step-by-step explanation:

Givens:

Mass of paper = 0.01 kg

inital speed of paper = 0 m/s (i.e at rest)

final speed of paper = 40 m/s

change in speed = (40 - 0 ) = 40 m/s

acceleration = change in speed / time taken = 40 / 0.05 = 800m/s²

force = mass x acceleration

= 0.01 kg x 800 m/s² = 8N