Question

A linear relationship exists between the natural logarithm of the vapor pressure of a gas and the reciprocal of its temperature (in kelvin). What is the slope of the line?

Answer 1

`\frac{-\Delta{H_(vap)}}{R}`

Step-by-step explanation:

The expression for Clausius-Clapeyron Equation is shown below as:

`\ln P = \frac{-\Delta{H_(vap)}}{RT} + c`

Where,

P is the vapor pressure

ΔHvap is the Enthalpy of Vaporization

R is the gas constant (8.314×10⁻³ kJ /mol K)

c is the constant.

THus, the slope of the line when natural logarithm of the vapor pressure of a gas is taken at y axis and the reciprocal of its temperature is taken at x axis is:-
`\frac{-\Delta{H_(vap)}}{R}`