Answer:
The equation of a line passing through the point (3 , 5) and parallel to Y = 1/2x + 4 is
A) y - 5 = 1/2 (x - 3)
Explanation:
Given:
equation of line
![y=(1)/(2)x + 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b5ae7e9btejojhdo3u417cqbf0xei90vol.png)
To Find:
The equation of a line passing through the point (3 , 5) and parallel to Y = 1/2x + 4
Solution:
Let A be the point A (x₁ ,y₁ ) ≡ (3 , 5)
on the required equation of a line.
As the required line is parallel slope of the line are equal.
On comparing the
![y=(1)/(2)x + 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b5ae7e9btejojhdo3u417cqbf0xei90vol.png)
equation with
slope =m =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ybjkeso7qr5r7js5h0mv9de35dih0sxfpl.png)
∴ slope of the required line is also m =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ybjkeso7qr5r7js5h0mv9de35dih0sxfpl.png)
as lines parallel.
We know that equation of line having slope m and passing through point (x₁ ,y₁ )is given by
![(y-y_(1))= m(x-x_(1))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cj14wvnb1jhzuit40pnwt6aypumtk1uvih.png)
so on substituting the above values i.e m=
and A (x₁ ,y₁ ) ≡ (3 , 5)
we get
![y-5=(1)/(2)(x-3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jj3aflhoy82cyy9hv6f66oep6j97bx6tm5.png)
∴
as per required