33.4k views
4 votes
How many real solutions are there for the following equation?

0=12x2+x−1
A
0

B
3

C
2

D
1

1 Answer

3 votes

Answer:

two real solutions (Answer C)

Explanation:

You can study the discriminator of this expression to find your answer.

Recall that the discriminator of a quadratic equation of the form:
ax^2+bx+c=0 is:
b^2-4ac

So for this equation,
a=12, \,b=1, \,and \,c=-1

Therefore, the discriminator gives:
(1)^2-4(12)(-1)=49 which is larger than zero.

This tells us that the equation has two real solutions.

User Jasoares
by
6.7k points